II. Reduction – gaining
electrons (valence becomes more negative)
A reductant is a compound that donates
electrons
III. Oxidation – losing
electrons (valence becomes more positive)
An oxidant is a compound that accepts
electrons
“LEO the lion says GER”
III. Redox potential
A. Arbitrary scale – how oxidized or reduced things
are compared to a standard
Standard reaction
:
B. Eh – electron flow relative to the
hydrogen
standard (electron potential)
As Eh decreases, the
solution
is more reduced (has more electrons to give) and as Eh increases, the
solution
is more
oxidized (will accept electrons).
average in lakes is ~300-500 mV
C. pE – the electron activity of a solution
- pE=-log[e-]
- measured at pH=7; =16.9 Eh
(so is related to electron potential)
Large and positive in
strongly
oxidizing solutions (low electron activity)
D. examples: half-reactions
1. Iron in oxygenated
waters
2. Sulfate reduction
Redox
reactions control the form of elements and the distribution of
different
forms of elements in lakes
V. Iron
A. Forms of oxygen
1. Fe2+ (ferrous)
< ~300 mv Eh
2. Fe3+ (ferric)
> ~300 mv Eh
B. Iron in oxygenated waters
C. Iron in anoxic waters
D. Significance –
1. Fe3+ binds
with P, element abundances are interrelated
2. as a limiting nutrient
VI. The Redox ‘Battlefield’ - Most reactions are mediated by
bacteria
A. Players in the ‘battle’
- One side – PS organisms
take light energy and make reduced compounds (local chemical
disequilibrium)
- Other side – using these
reduced compounds – heterotrophs extracting potential energy and
attempting
to reestablish
equilibrium
B. Who’s winning?
- Example: in a lake at
pH7, 25 degrees C, and oxygenated, predict that
- C is in CO2,
HCO3-, CO32-
- N is in NO3-
(no NH4+)
- S is in SO42-
(no H2S)
- oxidizers are winning
the war
if oxygen is available it will be used as a terminal electron acceptor
because it has a large free energy difference
VII. Reactions
A. How does this relate to energy? The free
energy depends on the energy difference between the reactants and the
products.
B. Gibbs free energy of reaction - Determines which reactions are most energetically favorable
deltaGo
= standard free energy of formation
R=gas constant (8.314 J
K-1 mol-1)
Keq=equilibrium
constant
T=temperature (K)
n=number of electrons involved
in the reaction
F=Faraday=23 kcal/mol
deltaE=difference
in redox potential in reaction
deltaG°’ = Sum (deltaG°’products) - Sum (deltaG°’reactants )
C. Biology behind this
The minimum energy necessary
to be useful to organisms is deltaGo=-7kcal/mol
– that is what is necessary or ATP formation
D. Redox reactions
1. Aerobic Respiration
(oxidation of organic matter)
a) reductant CHO, oxidant O2
b) Reaction:
c) delta Go = -686 kcal/mol
2. Nitrogen
a) NITRATE REDUCTION
(i) reductant CHO, oxidant NO3-
(ii) Reaction: DISSIMILATORY
NITRATE REDUCTION
(iii) delta Go'
= -649 kcal/mol
(iv) This is denitrification, reducing nitrate, NO3-,
to N2 gas
b) Assimilatory nitrate reduction
(i) Uptake of nitrate by an organism
(ii) Reaction:
c) Nitrification – production of
nitrate
(i) Reactions:
a) delta Go
= -65.7 kcal/mol
b) deltaGo
= -17.5 kcal/mol
(ii) So delta Go
1 = -65.7 kcal/mol
and delta Go 2 = -17.5 kcal/mol
(iii) This produces the source material for denitrification
3. Iron
IRON
OXIDATION
a) reductant Fe2+, oxidant O2
b) Reaction:
c) delta Go ’ = -10.6 kcal/mol
IRON
REDUCTION
a) Reaction:
b) Can occur with some oxygen present, but not energetically favorable
c) delta Go
’ = -300 kcal/mol
4. Sulfur
SULFATE
REDUCTION
a) reductant CHO, oxidant SO42-
b) Reaction:
c) delta Go
’ = -190 kcal/mol
SULFIDE OXIDATION
a) reductant HS-, oxidant O2
b) Reaction:
c) delta Go ’ = -190 kcal/mol
5. Methane
METHANOGENESIS
a) reductant H2, oxidant CO2
b) Reaction:
c) delta Go ’ = -8.3 kcal/mol
METHANE
OXIDATION
a) reductant CH4, oxidant O2
b) Reaction:
c) delta Go
’ = -193.5 kcal/mol
d) Whether methane can be oxidized with either SO42-
or NO3- is disputed
VIII. Oxidation of organic matter
A. Sediments

B. Other examples
1. Sediment profile:
What happened from time 1 to time 2?

2.

3.

4. You can also have the HS-
level
out before the sulfate concentration reaches low levels and stops
decreasing.
Why?

-Not
because of presence of O2 or NO3-
because
then SO42- reduction wouldn't proceed
-Often due to precipitation of pyrite: (see above)
for this to occur, there must be a source of Fe2+
5.
